Two identical glass bulbs are interconnected by a thin glass tube. A gas is filled in these bulbs at `N.T.P.` If one bulb is placed in ice and another bulb is placed in hot bath, then the pressure of the gas becomes `1.5` times. The temperature of hot bath will be

Options

A. `100^(@)C`
B. `182^(@)C`
C. `256^(@)C`
D. `546^(@)C`

Answer

D

Explanation

Quantity of gas in these bulbs is constant i.e., initial no. of moles in both bulb = Final number of moles
`mu_(1) + mu_(2) = mu_(1) + mu_(2)`
`(PV)/(R(273)) + (PV)/(R(273)) = (1.5 PV)/(R(273)) + (1.5 PV)/(R(T))`
`rArr (2)/(273) = (1.5)/(273) + (1.5)/(T) rArr T = 819 K = 546^(@)C`