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A gas is expanded from volume V(0) = 2V(...

A gas is expanded from volume `V_(0) = 2V_(0)` under three different processes. Process `1` is isobaric process, process `2` is isothermal and process `3` is adiabatic. Let `DeltaU_(1), DeltaU_(2) and DeltaU_(3)` be the change in internal energy of the gas in these three processes. then

A

`DeltaU_(1) gt DeltaU_(2) gt DeltaU_(3)`

B

`DeltaU_(1) lt DeltaU_(2) lt DeltaU_(3)`

C

`DeltaU_(2) lt DeltaU_(1) lt DeltaU_(3)`

D

`DeltaU_(2) lt DeltaU_(3) lt DeltaU_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A

(i) isobaric (ii) isothermal
`V prop T, DeltaU = +ve , Delta U = 0`
`V uarr, T , DeltaW = +ve`
(iii) `DeltaU lt 0, DeltaW gt0`
`(DeltaU)_(I) gt (DeltaU)_(II) gt (DeltaU)_(III)`
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