The IUPAC name of `CH_(3)C -= C CH (CH_(3))_(2)` is:

Options

A. 4-Methylpent -2-yne
B. 4, 4-Dimethylbut-2-yne
C. Methyl isopropyl acetylene
D. 2-Methylpent-4-yne

Explanation

To determine the IUPAC name of the compound `CH₃C≡CCH(CH₃)₂`, we will follow these steps:

### Step 1: Identify the Longest Carbon Chain
The first step is to identify the longest continuous carbon chain in the compound. In this case, we have:
- The chain consists of 5 carbon atoms: `C-C-C-C-C`.

### Step 2: Number the Carbon Chain
Next, we need to number the carbon chain in such a way that the carbon-carbon triple bond (alkyne) receives the lowest possible number. The structure can be represented as:
- `CH₃-C≡C-CH(CH₃)₂`.

If we start numbering from the left (1 to 5), we have:
1. CH₃ (1)
2. C (2)
3. C (3)
4. CH (4)
5. CH₃ (5)

The triple bond is between carbons 2 and 3.

### Step 3: Identify Substituents
Now we check for any substituents on the longest chain. In this case, there is a methyl group (–CH₃) attached to the fourth carbon:
- The substituent is a methyl group on carbon 4.

### Step 4: Combine the Information for the IUPAC Name
Now we can combine the information:
- The longest chain has 5 carbons: "pent".
- The triple bond is located at carbon 2: "2-yne".
- There is a methyl group on carbon 4: "4-methyl".

Putting it all together, the IUPAC name of the compound is:
**4-methylpent-2-yne**.

### Final Answer
The IUPAC name of `CH₃C≡CCH(CH₃)₂` is **4-methylpent-2-yne**.

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