A compound formed by two elements `M` and `N`. Element `N` forms ccp and atoms of `M` occupy `1//3rd` of tetrahedral voids. What is the formula of th compound?

Explanation

Let us suppose that,
the no. of atoms of N present in ccp = x
Since 1/3rd of the tetrahedral voids occupied by the atoms of M, therefore,
the no. of tetrahedral void occupied = 2x/3
The ratio of atoms of N and M in the compound = `x:2x//3or 3:2`
`therefore` The formula of the compound = `N_(3)M_(2)orM_(2)N_(3)`