Home
Class 12
CHEMISTRY
Melting point of RbBr (682^(@)C) is less...

Melting point of RbBr `(682^(@)C)` is lesser than that of NaF `(998^(@)C)`. Explain.

Text Solution

Verified by Experts

Both are crystalline solids and the melting points are directly linked to the respective lattice energies. Now, the magnitude of lattice energy is directly proporational to charge on ions and inversely to the interionic distance. In the above case both the cation shave +1 unit charge while anions have -1 unit charge. Since `Br^(-)` ions is bigger than `F^(-)` ion, the lattice energy for NaF crystals is more and therefore, the melting point is higher than of RbBr crystals.
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    DINESH PUBLICATION|Exercise QUESTION FROM BOARD EXAMINATION|80 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise HIGHER ORDER THINKING SKILLS (HOTS) QUESTIONS|7 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise N.C.E.R.T|77 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Ultimate Preparation|9 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|10 Videos

Similar Questions

Explore conceptually related problems

The melting point of RbBr is 682^(@)C , while that of NaF is 988^(@)C . The principla reason that melting point of NaF is much higher than that of RbBr is that :

The melting point of copper is higher than that of zinc because

Explain why melting point of NaCl is higher than that of AlCl_(3) .

Will the angle of dip in Russia be greater or lesser than that in India ? Explain.