What change occurs when AgCl is doped with `CdCl_(2)` ?

Explanation

Some `Ag^(+)` ions are replaced by `Cd^(2+)` ions due to smaller size. Actually to accommodate one `Cd^(2+)` ion, two `Ag^(+)` ions are to leave the lattice site in order to maintain electrical neutrality. One vacant position will be filled by `Cd^(2+)` ion while the other will remain vacant as a hole. This will lead to increased electrical conductivity of the solid.