Sodium crustallises in bcc unit cell. Calculate the approximate no. of unit cells in 9.2 grams of sodium.

Explanation

Number of Na atoms in 9.2 grams of the metal `=(6.023xx10^(23)xx(9.2g))/((23g))=2.41xx10^(23)` atoms
Number of Na atoms per bcc unit cell = 2
`therefore` Number of unit cells present `=(2.41xx10^(23))/(2)=1.205xx10^(23)`