In a solid ,oxide `(O^(2-))` ions are arranged in ccp, cations `(A^(3+))` occupy one -sixth of tetrahedral void and cations `(B^(3+))` occupy one -third of the octahedral voids . What is the formula of the compound?

Answer

`ABO_(3)`

Explanation

In ccp with each oxide, there would be 2 tetrahedral voids and one octahedral void. According to available data, `1//3^(rd)` octahedral voids are occupied by B and 1/6th tetrahedral voids by A. Therefore, the formula of the compound is `A_(2//6)B_(1//3)O or A_(2)B_(2)O_(6) or ABO_(3)`.