If the radius of `Br^(-)` ion is 0.182 nn, how large can a cation be fit in its tetrahedral holes ?

Answer

0.0753 pm

Explanation

For tetrahedral void, `r^(+)//r^(-)=0.225-0.414`
`r^(+)=(0.414)xxr^(-)` (For maximum radius of cation) ltBrgt `r^(+)=(0.414xx0.182"pm")=0.0753"pm"`. ltbr. Thus, cation of radius 0.0753 pm (maximum) can fit into each tetrahedral void.