Co-ordination number (CN) of barium ion `(Ba^(2+))` in `BaF^(2)` is 8. What is the CN of `F^(-)` ion ?

Answer

4

Explanation

C.N. of `Ba^(2+)` ions suggests that if is surrounded by eight `F^(-)` ions. `(8xx(-1)=-8)`. In order to balance eight negative charges, we need four `Ba^(2+)` ions. `therefore` C.N. of `F^(-)` ions = 4