Determine the type of cubic lattice to which a crystal belongs if the unit cell edge length is 290 pm and the density of crystal is `7.80g cm^(-3)`. (Molar mass = 56 a.m.u.)

Answer

bcc structure

Explanation

`Z=(rhoxxa^(3)xxN_(0)xx10^(-30))/(M)`
Density of unit cell `(rho)=7.8"g cm"^(-1)` , Major mass (M) = 56 amu = 56 g `mol^(-1)`
Avogadro's no. `(N_(0))=6.022xx10^(23)mol^(-1)` , Edge length of unit cell (A) = 290 pm = 290
`Z=((7.8cm^(-3))xx(290)^(3)xx(6.022xx10^(23)mol^(-1))xx(10^(-30)xxcm^(3)))/(("56 g"mol^(-1)))="2(bcc structure)."`