Home
Class 12
CHEMISTRY
Al (Atomic mass =27) crystallises in a c...

Al (Atomic mass =27) crystallises in a cubic system with edge length (a) equal to `4Å` its density is `2.7 g cm^(-3)` Calculate the number of aluminium atoms present per unit cell

Text Solution

Verified by Experts

Density `(rho)=(ZxxM)/(N_(0)xxa^(3))`
`2.7=(Zxx27)/(6.022xx10^(23)xx(4)^(3)xx(10^(-24)))`
`Z=(2.7xx6.022xx10^(23)xx(4)^(3)xx(10^(-24)))/27=4`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    DINESH PUBLICATION|Exercise Matrix|4 Videos
  • SOLID STATE

    DINESH PUBLICATION|Exercise Brain storming|10 Videos
  • SOLID STATE

    DINESH PUBLICATION|Exercise A.R|27 Videos
  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Ultimate Preparation|9 Videos
  • SOLUTIONS

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|10 Videos

Similar Questions

Explore conceptually related problems

Al (atomic mass =27) crystallises in a cubic system with edge length (a) equal to 4Å its density is 2.7 g//cm^(3) The type of the unit cell is:

Al ( at . Wt . 26.98 ) crystallizes in the cubic d system with a oo 4.05 Å . Its density is 2.7 g per cm^(3) . Determine the cell type Calculate the radius of Al atom .

An element occurs in bcc structure with edge length of 288 pm. Its density is 7.2 g//cm^3 Calculate atomic mass of element.

Aluminium(a.w=27) crystalises in a cubic unit cell with edge length (a)=100pm, with density 'd'=180g/cm, then type of unit cell is

Al crystallises in cubic shape unit cell and with edge length 405pm and density 2.7g/cc. Predict the type of crystal lattice.

An element with molor mass 27 g mol^(-1) forms a cubic unit cell with edge length 4.05 xx 10^(-8) cm . If its density is 2.7 g cm^(-3) , what is the nature of the unit cell?

An element A crystallises in fcc structure. 200 g of this element has 4.12xx10^(24) atoms. If the density of A is 7.2"g cm"^(-3) , calculate the edge length of the unit cell.