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One mole of symmetrical alkene upon ozon...

One mole of symmetrical alkene upon ozonolysis gives two moles of an aldehyde having the molecular mass `44 u`. Predict the alkene.

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Molecular mass of aldehyde `(C_(n)H_(2n)O) = 44 u`
`12 xx n + 2 xx n + 16 = 44` or `14n = 44 - 16 = 28 , n = 2`
Aldehyde is `C_(2)H_(4)O` and the corresponding alkene which gives the aldehyde upon ozonolysis is butene `(C_(4)H_(8))`.
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