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The pressure of a mixture of equal weigh...

The pressure of a mixture of equal weight of two gases of mol wt. 4 and 40, is 1.1 atm. The partial pressure of the lighter gas in this mixture is

A

0.55 atm

B

0.11 atm

C

1 atm

D

0.1 atm

Text Solution

Verified by Experts

The correct Answer is:
C
The partial pressure of the lighter gas
= mole faction `xx` total pressure
`= (W//4)/(W//4 + W//40) xx 1.1 = 1 atm`
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