The density of a gas at `27^(@)C` and 1 atm is `d`. Pressure remaining constant, at which of the following temperature will its density become `0.70 d` ?

Options

A. `20^(@)C`
B. `30^(@)C`
C. `400 K`
D. `300 K`

Answer

C

Explanation

`d = (PM)/(RT)`
or `(d_(1))/(d_(2)) = (T_(2))/(T_(1))` or `(d)/(0.75 d) = (T_(2))/(300)`
`T_(2) = (300)/(3) xx 4 = 400 K`