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50 mL of a gas A diffuse through a membr...

50 mL of a gas A diffuse through a membrane in the same time as for the diffusion of 40 mL of a gas B under identical pressure temperature conditions. If the molecular weight of `A = 64` that of B would be

A

100

B

250

C

200

D

80

Text Solution

Verified by Experts

The correct Answer is:
A
`(V_(1))/(V_(2)) = sqrt((M_(2))/(M_(1)))`
`(50)/(40) = sqrt((M_(2))/(64))`
or `sqrt(M_(2)) = (5)/(4) xx 8 = 10`
`M_(2) = 100`
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