The temperature of the gas is raised from `27^(@)C` to `927^(@)C`, the root mean square velocity is

Options

A. `sqrt(927//27)` times the earlier value
B. same as before
C. halved
D. doubled

Answer

D

Explanation

`(u_(1)^(2))/(u_(2)^(2)) = (T_(1))/(T_(2)) " or " (u_(1)^(2))/(u_(2)^(2)) = (300)/(1200) = (1)/(4)`
or `(u_(1))/(u_(2)) = (1)/(2) " or " u_(2) = 2u_(1)`