The internal energy of one mole of ideal gas is

Options

A. `3//2 RT`
B. `1//2 kT`
C. `1//2RT`
D. `3//2kT`

Answer

A

Explanation

K.E. `= (1)/(2) mv^(2) = (3)/(2) RT` (for 1 molecule)
For `n` moles `K.E. = (3)/(2) kT`
(`k =` Boltzmann's constant)