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The average kinetic energy of an ideal g...

The average kinetic energy of an ideal gas per molecule in SI units at `25^(@)C` will be

A

`6.17 xx 10^(-21) kJ`

B

`6.17 xx 10^(-21)J`

C

`6.17 xx 10^(-20) J`

D

`7.16 xx 10^(-20)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`K.E. = (3)/(2) KT = (3)/(2) (RT)/(N)`
`= (3)/(2) xx (8.314 KJ^(-1) mol^(-1) xx 298 K)/(6.023 xx 10^(23) mol^(-1))`
`= 6.17 xx 10^(-21) J`
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