In a mole of water vapours at STP, the volume actually occupied or taken by the molecules (i.e., Avogadro's No.`xx` volume of one molecule) is

Options

A. zero
B. less than 0.1% of 22.4 litres
C. about 10 % of the volume of the container of 22.4 litres
D. between 10% to 2% of 22.4 litres

Answer

B

Explanation

1 Mol of water = 18 g of water = `18 cm^(3)` of water
`:.` Actual volume of 1 mole of water molecule `= 18 cm^(3)`
Volume of 1 mole of water vapours at S.T.P. `= 22400 cm^(3)`
Percent volume actually occupied by water molecules
`= (18 xx 100)/(22400) = (9)/(112) lt 0.1%`