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The kinetic energy of two moles of N(2) ...

The kinetic energy of two moles of `N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))`

A

5491.6 J

B

6491.6 J

C

7491.6 J

D

8882.4 J

Text Solution

Verified by Experts

The correct Answer is:
C
`E = 3//2 nRT`
`= 3//2 xx 2 xx 8.314 JK^(-1) mol^(-1) xx 300 K`
`= 7491.6 JK^(-1) mol^(-1)`
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