Molar volume of `CO_(2)` is maximum at

Options

A. NTP
B. `0^(@)C` and 2.0 atm
C. `127^(@)C` and 1 atm
D. `273^(@)C` and 2.0 atm

Answer

C

Explanation

`PV = nRT`
Here `n = 1`
`V = (RT)/(P)`
At NTP
`V = (R xx 273)/(1) = 273 R`
At `0^(@)C (273 K)` and 2 atm
`V = (R xx 273)/(2) = (273 R)/(2)`
At `127^(@)C`(400K) and atm
`V = (R xx 400)/(1) = 400R`
At `273^(@)C` (546 K) and 2 atm
`V = (R xx 546)/(2) = 273 R`
Thus, molar volume is maximum at `127^(@)C` and 1 atm pressure