The pressure of temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

Options

A. `2 dm^(3)`
B. `3 dm^(3)`
C. `4 dm^(3)`
D. `8 dm^(3)`

Answer

C

Explanation

`P_(2) = 2P_(1)`
`T_(2) = 2T_(1)`
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`
`(P_(1) xx (4 dm^(3)))/(T_(1)) = ((2P_(1)) xx V_(2))/((2T_(1)))`
`:. V_(2) = 4 dm^(3)`