If the `v_(rms)` is `30R^(1//2)` at `27^(@)C` then calculate the molar mass of gas in kilogram.

Options

A. 1
B. 2
C. 4
D. 0.001

Answer

D

Explanation

`V_(rms) = sqrt((3RT)/(M)) " or " (30 R^(1//2))^(2) = (3RT)/(M)`
i.e., `900 R = (3R xx 300)/(M)`
or `M = 1 g mol^(-1) = 0.001 kg mol^(-1)`