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X mL of H(2) gas effuses through a hole ...

`X mL` of `H_(2)` gas effuses through a hole in a container in `5 s`. The time taken for the effusion of the same volume of the gas specified below, under identical conditions, is

A

10 sec, `H_(2)`

B

20 sec , `O_(2)`

C

25 sec, O

D

55 sec, `CO_(2)`

Text Solution

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The correct Answer is:
B
(a) is not possible because gas is same
(b) `(t_(1))/(t_(2)) = sqrt((M_(1))/(M_(2))) , (5)/(t_(2)) = sqrt((2)/(32)) " or " t_(2) = 20 sec`
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