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The rms velocity molecules of a gas of d...

The `rms` velocity molecules of a gas of density `4 kg m^(-3)` and pressure `1.2 xx 10^(5) N m^(-2)` is

A

`300 ms^(-1)`

B

`900 ms^(-1)`

C

`120 ms^(-1)`

D

`600 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`V_("rms") = sqrt((3P)/(d)) = sqrt((3 xx 1.2 xx 10^(5))/(4))`
`= sqrt(9 xx 10^(4)) = 300 ms^(-1)`
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