The pressure exerted by `6.0 g` of methane gas in a `0.03 m^(3)` vessel at `129^(@)C` is: (Atomic masses of `C= 12.01, H= 1.01 and R= 8.314 JK^(-1)mol^(-1)`)

Options

A. 215216 Pa
B. 13405 Pa
C. 41648 Pa
D. 31684 Pa

Answer

C

Explanation

Mass of `CH_(4), W = 6g`
Molecular mass of `CH_(4) = 12.01 + 4 xx 1.01 = 16.05`
`V = 0.03 m^(3), T = 129 + 273 = 402 K`
`PV = nRT = (W)/(M) RT`
`:. P = (W)/(m) xx (RT)/(V) = (6)/(16.05) xx 8.314 xx 402`
`= 41647.7 Pa = 41648 Pa`