Given RMS velocity of hydrogen at 300 K is `1.9 xx 10^(3) m//sec`. The RMS velocity of oxygen at 1200 K will be

Options

A. `7.6 xx 10^(3) m//sec`
B. `3.5 xx 10^(3) m//sec`
C. `0.95 xx 10^(3) m//sec`
D. `0.475 xx 10^(3) m//sec`

Answer

C

Explanation

`U_(H_(2))=sqrt((3Rxx300)/2)=1.9xx10^(3) ms^(-1)`
`U_(O_(2))=sqrt((3Rxx1200)/32)=2/4 sqrt((3Rxx300)/2)`
`=1/2xx1.7xx10^(3) ms^(-1)=0.95xx10^(3) ms^(-1)`