Two glass bulbs A and B are connected by a very small tube having a stop cock. Bulb A has a volume of 100 `cm^(3)` and contained the gas, while bulb B was empty. On opening th stop cock. The pressure fell down to 40%. The volume of the bulb B must be:

Options

A. `75 cm^(3)`
B. `125 cm^(3)`
C. `150 cm^(3)`
D. `250 cm^(3)`

Answer

C

Explanation

`V_(A) = 100 cm^(3) " " V_(B) = ?`
`P = P_(A) " " P_("new") = 0.4 P_(A)`
According to Boyle's law
`V_(A).P_(A) = P_("new") xx V`
`100 xx P_(A) = 0.4 P_(A) xx V_(A)`
or `V = 250 cm^(3)`
Since volume of bulb `A = 100 cm^(3)`
`:. V_(B) = 250 - 100 = 150 cm^(3)`