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A 2.24 L cylinder of oxygen at N.T.P. is...

A 2.24 L cylinder of oxygen at N.T.P. is found to develop of leakage. When the leakage was plugged the pressure dropped to 570 mm of Hg. The number of moles of gas that escaped escaped will be

A

0.025

B

0.05

C

0.075

D

0.09

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles originally present
`= (2.24)/(22.4) = 0.1`
After leakage, `n = (PV)/(RT)`
`= (570)/(760) xx (2.24)/(0.0-821) xx (1)/(273)`
`:.` No. of moles leaked out `= 0.1 - 0.075 = 0.025` mole
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