The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will be

Options

A. 0.6 m/sec
B. 0.3 m/sec
C. 0.9 m/sec
D. 3.0 m/sec

Answer

A

Explanation

`bar(v) = sqrt((8 RT)/(pi M)) :. (bar(v)_(1))/(bar(v)_(2)) = sqrt((T_(1))/(T_(2)))`
`bar(v)_(1) = 0.3 ms^(-1), T_(1) = 27^(2)C = 300 K`
`bar(v)_(2) = ?, T_(2) = 927^(@)C = 1200 K`
`(0.3 ms^(-1))/(bar(v)_(2)) = sqrt((300 K)/(1200 K))`
`:. bar(v)_(2) = 2 xx (0.3 ms^(-1)) = 0.6 ms^(-1)`