The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` is

Options

A. 4
B. 2
C. 1
D. `(1)/(4)`

Answer

C

Explanation

`mu = sqrt((3RT)/(M))`
`(mu_(1))/(mu_(2)) = sqrt((3RT_(1))/(M_(1)).(M_(2))/(3RT_(2))) = sqrt((T_(1)M_(2))/(M_(1)T_(2))`
`= sqrt((50 xx 32)/(800 xx 2)) = 1`