A gaseous mixture was prepared by taking equal moles of `CO` and `N_(2)`. If the total pressure of the mixture was found to be `1` atomosphere, the partical pressure of the nitrogen `(N_(2))` in the mixture is

Options

A. 0.9 atm
B. 1 atm
C. 0.5 atm
D. 0.8 atm

Answer

C

Explanation

`n(CO) = n (N_(2))`
`:. P(CO) = p(N_(2)) = p`(say)
This is because partial of a gas is proportional to its moles in mixture
`:. P(C) + p(N_(2)) = 1`
`p + p = 1`
`2p = 1`
`p = 1//2 = 0.5`
`p(N_(2)) = p = 0.5` atm