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The progress of the reaction A hArr nB w...

The progress of the reaction `A hArr nB` with time is presented in the figure given below:

Determine
a. The value of n.
b. The equilibrium constant K.
c. The initial rate of concentration of A.

A

2

B

1.2

C

0.5

D

6.67

Text Solution

Verified by Experts

The correct Answer is:
B
At equilibrium, there is no further change in conc. Hence, concentration at equilibrium are `[A]=0.3 "mol L"^(-1),[B] = 0.6 "mol L"^(-1)`
`:.` Equilibrium constant, `K=([B]^(2))/([A])=((0.6)^(2))/(0.3)`
`=1.2"mol L"^(-1)`.
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