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.(89)Ac^(227) is a member of actinium se...

`._(89)Ac^(227)` is a member of actinium series. Another member of the same series of

A

`""_(92)U^(235)`

B

`""_(90)TH^(232)`

C

`""_(89)Ac^(225)`

D

`""_(15)P^(34)`

Text Solution

Verified by Experts

The correct Answer is:
A
Actinium series in `4n+3` series i.e., when the mass no. is divided by 4 then a remainder of 3 should be left
`""^(235)U_(92)` i.e., 235/4=58+3/4
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