The maximum number of molecules is present in:-

Options

A. `15 L H_(2)` gas at STP
B. 5 L of `N_(20)` gas at STP
C. `0.5G H_(2)` gas
D. `10g" of " O_(2)` gas

Answer

A

Explanation

No. of molecules `= (15)/(22.4)xx N_(A) `
No. of molecules `=(5)/(22.4)xx N_(A)`
No. of molecules` = (0.5)/(2)xxN_(A)`
No. of molecules` = (10)/(32)xxN_(A) `
Hence 15 L `H_(2)` will have maximum munber of molescules