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In a compound A(X)B(Y) :-...

In a compound `A_(X)B_(Y)` :-

A

`"Mole of "A = "mole of " B" eq of " B="mole of "A_(x)B_(Y)`

B

eq of A = eq of B=eq of `A_(X)B_(Y)`

C

yx mole of A = yx mole of B = (x+y) mole of `A_(x)B_(y)`

D

yx mole of A = yx mole of B

Text Solution

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The correct Answer is:
B
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