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The valve of K(c) at 900 K temp for foll...

The valve of `K_(c)` at 900 K temp for following reaction is 5
`N_(2(g))+O_(2(g)) hArr 2NO_((g))` if equilibrium `conc^(n)` of `N_(2)` and `O_(2)` is 0.5M then value of `K_(p)` is :-

A

0.02

B

0.2

C

5

D

`(5)/(RT)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(p)=K_(c)(RT)^(Deltang)," " because Deltang=0`
`K_(p)=5`
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