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The equilibrium constant K(c) for the fo...

The equilibrium constant `K_(c)` for the following reaction at `842^(@)`C is `7.90xx10^(-3)`. What is `K_(p)`at same temperature ?
` (1)/(2)F_(2(g)) hArr F_(g)`

A

`8.64xx10^(5)`

B

`8.26xx10^(-4)`

C

`7.90xx10^(-2)`

D

`7.56xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(P)=(7.9xx10^(-3))xx(0.0821xx115)^(0.5)`
`K_(P)=7.56xx10^(-2)`
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