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NH(4)HS(s)hArrNH(3(g))+H(2)S(g) The eq...

`NH_(4)HS_(s)hArrNH_(3(g))+H_(2)S_(g)`
The equilibrium pressure at `25_(@)`C is 0.660 atm What is `K_(p)` for reactoin ?
`NH_(4)NH_(s)hArrNH_(3(g))+H_(2)S_(g)`

A

0.109

B

0.218

C

1.89

D

2.18

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(,NH_(4)HS,hArr,NH_(3(g)),+H_(2)S_((g))),("at equilibrium",,,P,P):}`
`P_(Total) = 2P = 0.66`
P = 0.33 atm
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