Home
Class 12
CHEMISTRY
At 25^(@)C the equilibrium constant K,an...

At `25^(@)`C the equilibrium constant K,and `K_(2)` of two reaction are
`2NH_(3)hArrN_(2)+3H_(2) ,K_(1)`
`(1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3),K_(2)`
The relation `b//w` two equilibrium constant is :-

A

`K_(1)=K_(2)`

B

`K_(2)=(1)/(K_(1)^(2)`

C

`K_(1)=(1)/(K_(2)^(2)`

D

`K_(1)=(1)/(K_(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos
  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

If K_(1) represents the equilibrium constant for reaction: H_(2)+I_(2)hArr2HI & K_(2)" for "(1)/(2)H_(2)+(1)/(2)I_(2)hArr HI the relation between K_(1)& K_(2) would be

For the reaction N_(2)+3H_(2)hArr2NH_(3) and (1)/(2)N_(2)+(3)/(2)H_(2)hArrNH_(3) write down the expression for equilibrium constants K_(c ) and K_(c )^(') . How is K_(c ) related to K_(c )^(') ?

The equilibrium constant for the reversible reaction N_(2)+3H_(2) hArr 2NH_(3) is K and for the reaction (1)/(2) N_(2)+(3)/(2) H_(2) hArr NH_(3) , the equilibrium constant is K',.K and K' will be related as

The following equilibrium constants are given : N_(2) + 3 H_(3) hArr 2 NH_(3) , K_(1) N_(2) + O_(2) hArr 2 NO , K_(2) H_(2) + 1/2 O_(2) hArr H_(2) O , K_(3) The equilibrium constant for the oxidation of NH_(3) by oxygen to give NO is :

consider the following gaseous equilibrium with equilibrium constant K_(1) and K_(2) respectively SO_(2)(g)+ 1//2O_(2)hArrSO_(3)(g) 2SO_(3)(g)hArr2SO_(2)(g)+O_(2)(g) The equilibrium constants are related as