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The degree of dissociation of acetic aci...

The degree of dissociation of acetic acid in a 0.1 M solution is `1.32xx10^(-2)`, find out the pKa :-

A

5.75

B

3.75

C

4. 00

D

4. 75

Text Solution

Verified by Experts

The correct Answer is:
D
`Ka=Calpha^(2)0.1xx(1.32xx10^(-2))^(2)=1.74xx10^(-5)`
`pKa=5-log1.74=5-0.26`
=4.74
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