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The solubility of PbF(2) (formula mass =...

The solubility of `PbF_(2)` (formula mass =245) is 0.46 g/L. What is the solubility product?

A

`1.1xx10^(-10)`

B

`2.6xx10^(-8)`

C

`1.1xx10^(-7)`

D

`16.8xx10^(-9)`

Text Solution

Verified by Experts

The correct Answer is:
B
`S=(0.46)/(245)=187xx10^(-3)M`
`Ksp=4S^(3)`
`=4xx(187xx10^(-3))^(3)`
`Ksp=2.6xx10^(-8)`
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