Home
Class 12
CHEMISTRY
For vaporization of water at 1 atmospher...

For vaporization of water at 1 atmospheric pressure the values of `DeltaH` and `DeltaS` are `40.63KJmol^(-1)` and `108JK^(-1)mol^(-1)` , respectively. The temperature when Gibbs energy change `(DeltaG)` for this transformation will be zero is

A

395.3 K

B

375.9 K

C

373 K

D

380 K

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos
  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos
  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos
  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

For vaporization of water at 1 atmospheric pressure, the values of DeltaH and DeltaS are 40.63 "kJ mol"^(-1) and 108.8 "JK"^(-1) mol^(-1) respectively. The temperature when Gibbs energy change (DeltaG) for this transformation will be zero , is :

For vaporization of water at 1 atmospheric pressure the values of Delta H and Delta S are 50.63 kJ mol^9-1) and 118.8 JK ^(-1) mol^(-1) respectively. The temperature when Gibbs energy change (Delta G) for this transformation will be zero, is

For a certain reaction X rarr Y the value of DeltaH and DeltaS are 50.50KJ mol^(-1) and 100.03JK^(-1) respectively. The temperature at which DeltaG=0 is

For the reaction, Ag_(2)O(s)hArr2Ag(s)+(1)/(2)O_(2)(g) DeltaH,DeltaS and T are 40.63 kJ mol^(-1) , 108.8 JK^(-1)mol^(-1) and 373.4K respectively. Free energy change DeltaG of the reaction will be:

For the reaction Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g) the value of Delta H=30.56 KJ mol^(_1) and Delta S = 66 JK^(-1)mol^(-1) . The temperature at which the free energy change for the reaction will be zero is :-

The value of DeltaH and DeltaS for a reaction are respectively 30 kJ mol^(-1) and 100JK^(-1)mol^(-1) . Then temperature above which the reaction will become spontaneous is: