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Standard enthalpy of vapourisation Delta...

Standard enthalpy of vapourisation `DeltaH^(@)` forwater is `40.66 KJ mol^(-1)`.The internal energy of vapourisation of water for its 2 mol will be :-

A

`+43.76`

B

`+40.66`

C

`+37.56`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)O(l)toH_(2)O(g)`
`DeltaH^(@)=DeltaE^(@)+Deltan_(g)RT`
`40.66=66DeltaE^(@)+(1xx8.314xx373)/(1000)`
`DeltaE^(@)=+37.56KJ//mol`
for 2 mole `DeltaE^(@)=2xx37.26=75.12KJ`
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