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Moldydenum ("At. mass=96g//mol"^(-1)) cr...

Moldydenum `("At. mass=96g//mol"^(-1))` crystallizes as bcc crystal. If density of crystal is `10.3g//cm^(3)`, then radius of Mo atoms `(use N_(A)= 6 xx 10^(23))`:

A

11pm

B

314pm

C

135.96pm

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`d=(ZxxM)/(a^(3)xxN_(A))`
`10.3=(2xx96)/(a^(3)xx6xx10^(23))`
`a=3.14xx10^(-8)cm=314"pm"`
`r=sqrt(3a)/(4)=135.96 "pm"`
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