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When AgCI is dopped with 0.01 mole CdCI(...

When AgCI is dopped with 0.01 mole `CdCI_(2)`, What is number of cationic vacancies ?

A

`0.02 N_(A)`

B

`0.01N_(A)`

C

0.01

D

0.02

Text Solution

Verified by Experts

The correct Answer is:
B
When AgCl is dopped with `CdCI_(2)` No. of `Cd^(+2)` added = No. of cation vacancies.
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