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In a solid ,oxide (O^(2-)) ions are arr...

In a solid ,oxide `(O^(2-))` ions are arranged in ccp, cations `(A^(3+))` occupy one -sixth of tetrahedral void and cations `(B^(3+))` occupy one -third of the octahedral voids . What is the formula of the compound?

A

`A_(2)BO_(3)`

B

`A_(2)B_(2)O_(3)`

C

`ABO_(3)`

D

`AB_(2)O_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`O^(-2)" forms ccp "to4`
A occupy ` (1)/(6)th " of " THVto(1)/(6)xx8=(4)/(3)`
`" B occupy " (1)/(3)rd" of" OHV rArr (1)/(3)xx4=(4)/(3)`
`" Formula ", A_((4)/(3))B_((4)/(3))O_(4)rArrABO_(3)`
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