Home
Class 12
CHEMISTRY
What will be the mass percentage of resu...

What will be the mass percentage of resulting solution prepared by mixing 15% (w/w) 500g aqueous solution of urea with 25% (w/w)400g aqueous solution of it :-

A

0.18

B

0.2

C

0.25

D

0.15

Text Solution

Verified by Experts

The correct Answer is:
B
Amount of urea `= (15)/(100)xx500+(25)/(100)xx400`
`=75+100=175g`
`%w//w=(175)/(900)xx100=19.44%`
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

Molality of 20% (w/w) aq. glucose solution is

Calculate the mass precent of a solution obtine by mixing 100 g of 10% urea solution with 150 g of 15% urea solution.

0.06% (W/V) aqueous solution of urea is isotonic with ______.

18% (w/V) solution of urea (Mol. Mass=60) is

What will be the osmayic pressure of 5%(w/v) aqueous solution of urea at 17^(@) C ?

What will be the molality of a solution of glucose in water which is 10% w // W ?

6% (W/V) solution of urea will be isotonic with: