Home
Class 12
CHEMISTRY
0.1 molal solution of Hg(NO(3))(2) free...

0.1 molal solution of `Hg(NO_(3))_(2)` freezes at `-.558^(@)` C. The cryoscopic constant for water is 1.86 KKg `mol^(-1)` then what will be the percentage ionisation of salt ?

A

`33.33%`

B

`50%`

C

`75%`

D

`100%`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise INORGANIC CHEMISTRY|300 Videos

  • CHEMISTRY AT A GLANCE

    ALLEN|Exercise ORGANIC CHEMISTRY|483 Videos

  • Chemical Equilibrium

    ALLEN|Exercise All Questions|24 Videos

  • ELECTROCHEMISTRY

    ALLEN|Exercise EXERCISE -05 [B]|38 Videos

Similar Questions

Explore conceptually related problems

The freezing point of 0.1 molal aq. Solution of K_(X)[Fe(CN)_(6)] is -0.744^(@) C. The molal depression constant of water is 1.86 K-kg mol^(-1) . If the salt behaves as strong electrolyte in water, the value of X is :

The freezing point of a 1.00 m aqueous solution of HF is found to be -1.91^(@)C . The freezing point constant of water, K_(f) , is 1.86 K kg mol^(-1) . The percentage dissociation of HF at this concentration is:-

0.1mole aqueous solution of NaBr freezes at - 0.335^@C at atmospheric pressure , k_f for water is 1.86^@C . The percentage of dissociation of the salt in solution is

0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If K_(f) for water is 1.86K kg mol^(-1) , the lowering in freezing point of the solution is

Calulate the molesules mass of a substance whose 7.0% by mass solution in water freezes at -0.93^(@)C . the cryosctopic constant of water is 1.86^(@)C kg mol^(-1) :